Poste Monopolo
FACTOR DE AMPLIFICACIÓN DINÁMICOzs = 11.5 m VD(zs) = 26.29 m/s Fα(zs) = 0.56 Iv(zs) = 0.28 zmín = 5.0 α = 0.61 L(zs) = 52.54 B2 = 0.77 SL(zs, n1,x) = 0.04 ηh = 1.67 Rh(ηh) = 0.43 ηb = 3.34 Rb(ηb) = 0.25 R2 = 1.72 ν = 2.64 kp = 3.99 FAD = 1.53 FUERZAS SOBRE EL LETREROViento Normal al Plano (θ = 0°)Fe = CPn KP qH Aexp FAD = 1.47 (1.0) (1097.95) (18.0) (1.53) = 44487.99 N Viento a 45°El punto de aplicación de la fuerza se localizará a una excentricidad definida como se muestra en la figura 4.3.15 del manual. Excentricidad (e) = 1.2 Fe = CPn KP qH Aexp FAD = 1.47 (1.0) (1097.95) (18.0) ( 1.53) = 44487.99 N Viento Paralelo al Plano (θ = 90°)
FUERZAS Y PRESIONES EN EL SOPORTEVIENTO NORMAL AL PLANO (θ = 0°) Ca = 0.75 Para z = 0.5 m: Frz = 0.88 Vd = 149.77 km/h qz = 1051.1 Pa Pz = 784.76 N (80.0 kg) Fe = 610.03 N/m(62.18 kg/m) Para z = 1.5 m: Frz = 0.88 Vd = 149.77 km/h qz = 1051.1 Pa Pz = 784.76 N (80.0 kg) Fe = 610.03 N/m(62.18 kg/m) Para z = 2.5 m: Frz = 0.88 Vd = 149.77 km/h qz = 1051.1 Pa Pz = 784.76 N (80.0 kg) Fe = 610.03 N/m(62.18 kg/m) Para z = 3.5 m: Frz = 0.88 Vd = 149.77 km/h qz = 1051.1 Pa Pz = 784.76 N (80.0 kg) Fe = 610.03 N/m(62.18 kg/m) Para z = 4.5 m: Frz = 0.88 Vd = 149.77 km/h qz = 1051.1 Pa Pz = 784.76 N (80.0 kg) Fe = 610.03 N/m(62.18 kg/m) Para z = 5.5 m: Frz = 0.88 Vd = 149.77 km/h qz = 1051.1 Pa Pz = 784.76 N (80.0 kg) Fe = 610.03 N/m(62.18 kg/m) Para z = 6.5 m: Frz = 0.88 Vd = 149.77 km/h qz = 1051.1 Pa Pz = 784.76 N (80.0 kg) Fe = 610.03 N/m(62.18 kg/m) Para z = 7.5 m: Frz = 0.88 Vd = 149.77 km/h qz = 1051.1 Pa Pz = 784.76 N (80.0 kg) Fe = 610.03 N/m(62.18 kg/m) Para z = 8.5 m: Frz = 0.88 Vd = 149.77 km/h qz = 1051.1 Pa Pz = 784.76 N (80.0 kg) Fe = 610.03 N/m(62.18 kg/m) Para z = 9.5 m: Frz = 0.88 Vd = 149.77 km/h qz = 1051.1 Pa Pz = 784.76 N (80.0 kg) Fe = 610.03 N/m(62.18 kg/m) |